Question

Find the area of a triangle whose sides are 13 cm, 14 cm and 15 cm.

Answer 1

Given sides of triangle

$a=13,b=14,c=15$

Semi-perimeter $s=\frac{1}{2}(a+b+c)=\frac{1}{2}(13+14+15)=21$

Area, A = $\sqrt{s(s-a)(s-b)(s-c)}$

$A=\sqrt{21(21-13)(21-14)(21-15)}$

$A=84$ $c{m}^2$