Question

# Find the area of a triangle whose sides are $$15$$ cm, $$8$$ cm and $$17$$ cm

A
120cm2
B
68cm2
C
136cm2
D
60cm2

Solution

## The correct option is D $$60\displaystyle cm^{2}$$Area of triangle with sides a, b, and c and s $$= \dfrac { a+b+c }{ 2 }$$ is $$\sqrt { s(s-a)(s-b)(s-c) }$$. For triangle with sides 15 cm, 8 cm and 17 cm, $$s = \dfrac { 15+8+17 }{ 2 } =20 cm$$Area of the triangle with sides 15 cm, 8 cm and 17 cm $$=\sqrt { 20(20-15)(20-8)(20-17) }$$$$=\sqrt { 20\times 5\times 12\times 3 }$$$$=\sqrt { 4\times 5\times 5\times 4\times 3\times 3 }$$$$= 4\times 5\times 3 = 60 {cm}^{2}$$Mathematics

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