Question

Find the area of a triangle whose sides are $18$ cm, $24$ cm and $30$ cm.

• A. $356$ sq.cm;
• B. $216$ sq.cm;
• C. $276$ sq.cm;
• D. $366$ sq.cm;

Answer 1

The correct option is B $216$ sq.cm;

Given, sides of triangle 18 cm, 24 cm, 30 cm.
Now,Semi perimeter, s=$=\frac{Sumofsidesoftriangle}{2}=\frac{18+24+30}{2}=36cm$
Using heron's formula, Area of triangle$=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{36(36-18)(36-24)(36-30)}=\sqrt{36\times 18\times 12\times 6}=216{cm}^2$