Question

Find the area of a triangle whose sides are 48cm, 14cm and 50 cm.

• A. 336 $c{m}^2$
• B. 330 $c{m}^2$
• C. 265 $c{m}^2$
• D. 305 $c{m}^2$

Answer 1

The correct option is A

336 $c{m}^2$

Let a = 48cm, b = 14cm and c = 50 cm

semi perimeter s = $\frac{a+b+c}{2}$

=$\frac{48+14+50}{2}$ = 56 cm.

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

= $\sqrt{56\times 8\times 42\times 6}$

= $\sqrt{8\times 7\times 8\times 7\times 6\times 6}$

= 8 x 7 x 6

= 336 $c{m}^2$