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Question

Find the area of a triangle whose two sides are 8 cm and 11cm and the perimeter is 32cm.

A
8cm2
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B
830cm2
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C
830cm2
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D
24cm2
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Solution

The correct option is B 830cm2
Let third side be x
Perimeter =8+11+x
19+x=32
x=13
s=322=16
Heron's formula
A=s(sa)(sb)(sc)
=16(168)(1611)(1613)
=16×8×5×3
=830 cm2

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