Question

Find the area of a triangle with sides $a=3cm,b=2cm,c=4cm$.

Answer 1

Given $a=3cm,b=2cmandc=4cm$

Using the formula

$Area=\sqrt{s(s-a)(s-b)(s-c)}$

Semi-perimeter, $s=\frac{a+b+c}{2}$

$=\frac{3+2+4}{2}$

$s=\frac{9}{2}cm$

$Area=\sqrt{\frac{9}{2}(\frac{9}{2}-3)(\frac{9}{2}-2)(\frac{9}{2}-4)}c{m}^2$

$Area=\sqrt{\frac{9}{2}\left(\frac{3}{2}\right)\left(\frac{5}{2}\right)\left(\frac{1}{2}\right)}c{m}^2$

$Area=\sqrt{\frac{135}{16}}c{m}^2$

$Area=2.904c{m}^2$