Find the area of cardboard required to prepare a closed box of dimensions $12 c m \times 10 c m \times 8 c m$ .

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Solution

Total Surface area of a cuboid is given by $T . S . A = 2 (l b + b h + h l)$ where $l, b, h$ are dimensions of cuboid.
Given $l = 12 c m, b = 10 c m, h = 8 c m$
$T . S . A = 2 ((12) (10) + (10) (8) + (8) (12))$
$= 2 (120 + 80 + 96)$
$2 (296) = 592 c m^{2}$
Area of cardboard required to prepare a closed box of given dimensions $= 592 c m^{2}$

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