Find the area of parallelogram given in the below figure.
$[2 M a r k s]$

Open in App

Solution

Base = 9 in

Height = 7 in

Area of parallelogram = base x height
$[1 M a r k]$

= 9 x 7 in²

= 63 in²
$[1 M a r k]$

Suggest Corrections

Similar questions

Find the perimeters and area of the parallelograms given in figure. [3 MARKS]

Q. In the figure given below, ABCD is a parallelogram. ABE is a right-angled triangle whose area is 32 cm

^{2}

. Find the area of the parallelogram.

Find the area of the figure given below (in sq. inches). [4 MARKS]

Q. In the figure given below, the area of parallelogram ABCD is:

In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of parallelogram is $156 c m^{2}$ then find the length of AL. [2 MARKS]

Join BYJU'S Learning Program

Find the area of parallelogram given in the below figure. [2 Marks]

Base = 9 in Height = 7 in Area of parallelogram = base x height [1 Mark] = 9 x 7 in2 = 63 in2 [1 Mark]

Find the area of parallelogram given in the below figure.
$[2 M a r k s]$

Base = 9 in

Height = 7 in

Area of parallelogram = base x height
$[1 M a r k]$

= 9 x 7 in²

= 63 in²
$[1 M a r k]$