Question

Find the area of rectangle whose length is 2 more than width and perimeter is given as 36cm

Answer 1

Let the width be $x$

Length of rectangle is $2$ more than width $⟹x+2$

Perimeter is given as $2(l+b)=362(x+x+2)=362x+2=182x=18-2x=\frac{16}{2}x=8$

So length is $x+2=8+2=10$

Area of rectangle is given as $lb=\left(10\right)\left(8\right)=80c{m}^2$