Question

Find the area of right angled triangle whose hypotenuse is $13cm$ and base is $12cm$.

Answer 1

Consider the $△ABC$,

where$AC=13cm;BC=12cm$ by phythagorus theorm

${AC}^2={AB}^2+{BC}^2\Rightarrow {AB}^2={AC}^2+{BC}^2\therefore AB=\sqrt{{13}^2-{12}^2}=5cm$

Area of $△ABC=\frac{1}{2}\times \text{base}\times \text{height}=\frac{1}{2}\times AB\times BC=\frac{1}{2}\times 12\times 5=30{cm}^2$.