Question

Find the area of shaded region in the given figure , if PQ = 24 cm, PR = 7 cm, and O is the center of the circle.

Answer 1

$△RPQ$ is right angle at $P$.

(Angle made in a semicircle right angle)

$R{Q}^2=R{P}^2+P{Q}^2$

Put values of $RPandPQ$

$RQ=25$

$RQ$ is diameter of given circle.

Area of shaded region $=\frac{\pi r^2}{2}-$ Area of $△RPQ$

Area of $△RPQ$ $=\frac{1}{2}PQ\times PR$

Put values of $PQandPR$

Area of $△RQP$= $84c{m}^2$

Area of shaded region $=\frac{\pi 625}{8}$ $-84$

$=161.3125$ $c{m}^2$