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Question

Find the area of the major sector of a circle with radius 42 cm and of angle 30°.
(Use π = 227


  1. 5082

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Solution

The correct option is A 5082
Given sector is OAPB,

Area of the minor sector
=θ360×πr2
=30360×π×r2
=112×πr2
=πr212

Area of the major sector=Area of the circleArea of the minor sector
Area of the major sector=(πr2 πr212) cm2
Area of the major sector=(12πr2πr212) cm2
Area of the major sector=(11πr212) cm2

Now, using π=227
Area of the major sector=(11×22×42×4212×7) cm2
Area of the major sector=11×11×42 cm2
Area of the major sector=121×42 cm2
Area of the major sector=5082 cm2





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