Find the area of the rectangle with length 3-4 m and breadth is 2 times the length-A- 4-9 sq- mB- y-8 sq- m C- 8-9 sq- mD- 9-4 sq- m

The correct option is B 9/8 sq. m Length nbsp; = nbsp;3/4 m nbsp; breadth is 2 times the length so, breadth = nbsp;2×3/4 = nbsp;3/2 m area of rectang ...

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Standard VI

Mathematics

Calculating Fractional Area

Find the area...

Question

Find the area of the rectangle with length $\frac{3}{4} m$ and breadth is 2 times the length.

$\frac{4}{9}$ sq. m

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$\frac{9}{8}$ sq. m

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$\frac{8}{9}$ sq. m

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$\frac{9}{4}$ sq. m

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Solution

The correct option is B
$\frac{9}{8}$ sq. m

Length = $\frac{3}{4} m$

breadth is 2 times the length so, breadth = $2 \times \frac{3}{4}$ = $\frac{3}{2} m$

area of rectangle = length x breadth = $\frac{3}{4} \times \frac{3}{2} = \frac{9}{8}$ sq. m

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Find the area of the rectangle with length 34m and breadth is 2 times the length.

The correct option is B 98 sq. m Length = 34m breadth is 2 times the length so, breadth = 2×34 = 32m area of rectangle = length x breadth =34×32=98 sq. m

Find the area of the rectangle with length $\frac{3}{4} m$ and breadth is 2 times the length.

The correct option is B
$\frac{9}{8}$ sq. m

Length = $\frac{3}{4} m$

breadth is 2 times the length so, breadth = $2 \times \frac{3}{4}$ = $\frac{3}{2} m$

area of rectangle = length x breadth = $\frac{3}{4} \times \frac{3}{2} = \frac{9}{8}$ sq. m