Question

Find the area of the shaded portion. A circle in inscrided in a square such that both their centres coincide. BDE is an isosceles triangle. Side of a square is 10 m.
[4 MARKS]

Answer 1

Process : 3 Marks
Result : 1 Mark

Area of the square is (10) $\times$ (10) = 100 $m^2$

Given diameter of circle = 10 m

Radius of the circle= 5 m

Area of the circle

= $\pi$ $\times$ ($5^2$)

= 78.5$m^2$

Area of the triangle

= 0.5 $\times$ (BD) $\times$ (DE)

= 0.5 $\times$ (10) $\times$ (10)

= 50 $m^2$

Area of the shaded region

=Area of square - Area of circle + Area of triangle

= 71.5 $m^2$