Question

Find the area of the square, the length of whose diagonal is
(i) $72cm$
(ii) $2.4m$

Answer 1

(i) Diagonal of the square $=72cm$
Area of the square $=\frac{1}{2}\times$ Diagonal${}^2$ sq. units
$=\frac{1}{2}\times {\left(72\right)}^2{cm}^2$
$=\frac{1}{2}\times 72\times 72$
$=2592{cm}^2$
(ii) Diagonal of the square $=2.4m$
Area of the square $=\frac{1}{2}\times$ Diagonal${}^2$ sq. units
$=\frac{1}{2}\times (2.4{)}^2{m}^2$
$=2.88m^2$