Find the area of the triangle PQR with base and height as 36 in and 45 in respectively.

810 sq.in

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1080 sq.in

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1215 sq.in

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1620 sq.in

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Solution

The correct option is A 810 sq.in
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ P Q R = \frac{1}{2} \times Q R \times P S$

$= \frac{1}{2} \times 36 \times 45$

= 810 sq. in

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Find the area of the triangle PQR with base and height as 36 in and 45 in respectively.

The correct option is A 810 sq.inArea of triangle = 12× Base× Height ∴Area of ΔPQR=12×QR×PS =12×36×45 = 810 sq. in

The correct option is A 810 sq.in
$Area of triangle = \frac{1}{2} \times Base \times Height$

$∴ Area of Δ P Q R = \frac{1}{2} \times Q R \times P S$

$= \frac{1}{2} \times 36 \times 45$

= 810 sq. in