Question

Find the area of trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.

Answer 1

Length of parallel sides of a trapezium are 16 dm and 22 dm,i.e.$b_1=16dm,b_2=22dmandheight\left(h\right)=12dm$

$\therefore Areaoftrapezium=\frac{1}{2}(b_1+b_2)\times h=\frac{1}{2}(16+22)\times 12d{m}^2=\frac{1}{2}\times 38\times 12d{m}^2=228d{m}^2$