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Area of Trapezium by Finding the Area of a Triangle of Same Area

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Question

Find the area of trapezium with base 15 cm and height 8 cm.If the side parallel to the given base is 9 cm long.

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Solution

In a trapezium ABCD,

$B a s e A B = 15 c m a n d D C = 9 c m, h e i g h t D L = 8 c m ∴ A r e a = \frac{1}{2} (s u m o f b a s e s) \times h e i g h t = \frac{1}{2} (A B + D C) \times D L = \frac{1}{2} (15 + 9) \times 8 c m^{2} = \frac{1}{2} \times 24 \times 8 c m^{2} = 96 c m^{2}$

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Area of Trapezium by Finding the Area of a Triangle of Same Area

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