Question

Find the average of the smallest and the greatest three-digit numbers that are divisible by 13 .

• A. 546
• B. 1092
• C. 104
• D. 988

Answer 1

The correct option is A 546

Consider a number 100 divided by 13 and remainder is 9

so 100+(13-9)=104 is smallest number required

now consider a number 999 divided by 13 we get remainder 11

so 999-11=988 is largest number required

$\therefore$average = $\left(\frac{104+988}{2}\right)=546$