Find the average speed of a car which covers a distance of 14 km in the first 15 minutes and 10 km in the next 15 minutes.

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Solution

Total distance covered = 14 + 10 = 24 km

Total time = 15 + 15 = 30 minutes or $\frac{1}{2}$ hr

Average speed $= \frac{Total distance}{Total time}$
$= \frac{24 k m}{\frac{1}{2} h r s} = 48 k m / h r$

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Find the average speed of a car which covers a distance of 14 km in the first 15 minutes and 10 km in the next 15 minutes.

Total distance covered = 14 + 10 = 24 km Total time = 15 + 15 = 30 minutes or 12 hr Average speed =Total distanceTotal time =24 km12 hrs=48 km/hr

Total distance covered = 14 + 10 = 24 km

Total time = 15 + 15 = 30 minutes or $\frac{1}{2}$ hr

Average speed $= \frac{Total distance}{Total time}$
$= \frac{24 k m}{\frac{1}{2} h r s} = 48 k m / h r$