Find the average speed of a train which is travelling x km in the 1^{$^{s t}$} hour and 2y km in the 2^{$^{n d}$} hour.

(x+y)/3 km/hr

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(x+2y)/2 m/s

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(x+2y)/2 km/hr

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0 m/s

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Solution

The correct option is C
(x+2y)/2 km/hr

Total distance travelled = Distance travelled in the 1^{$^{s t}$} hour + Distance travelled in the 2^{$^{n d}$} hour.

= x + 2y km

Total time taken= 1+1= 2hrs

Average speed $= \frac{T o t a l d i s t a n c e t r a v e l l e d}{T o t a l t i m e t a k e n} = \frac{x + 2 y}{1 + 1} = \frac{x + 2 y}{2}$ km/hr

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Find the average speed of a train which is travelling x km in the 1st hour and 2y km in the 2nd hour.

The correct option is C (x+2y)/2 km/hr Total distance travelled = Distance travelled in the 1st hour + Distance travelled in the 2nd hour. = x + 2y km Total time taken= 1+1= 2hrs Average speed=Total distance travelledTotal time taken=x+2y1+1=x+2y2 km/hr

Find the average speed of a train which is travelling x km in the 1^{$^{s t}$} hour and 2y km in the 2^{$^{n d}$} hour.