Find the average velocity of a projectile between the instants it crosses half the maximum height. It is projected with a speed u at an angle $θ$ with the horizontal.

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Solution

Time of flight $T = \frac{2 u s i n θ}{g}$

Average velocity $= \frac{c h a n g e i n d i s p l a c e m e n t}{t i m e}$

From the given data, it can be taken as horizontal. So there is no effect of vertical component of the velocity during this displacement.

Because the body moves at a constant speed of $u c o s θ$ in horizontal direction.

The average velocity during this displacement will be $u c o s θ$ in the horizontal direction.

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Find the average velocity of a projectile between the instants it crosses half the maximum height. It is projected with a speed u at an angle θ with the horizontal.

Find the average velocity of a projectile between the instants it crosses half the maximum height. It is projected with a speed u at an angle $θ$ with the horizontal.