Question

Find the average velocity of a projective between the instands it crosses half the maximum height. It is projected with a speed u at angle $\theta$ with the horizontal.

Answer 1

Time if flight,

T = $\frac{2usin\theta }{g}$

Average velocity = $\frac{\text{Change in displacement}}{\text{time}}$

From the figure, it can be said that AB is horizontal. So there4 is no effect, of vertical component of the velocity during this displacement. As the body moves at a constant displacement, 'u cos $\theta$ in horizontal direction, the average velocity during this displacement will be u cos $\theta$ in the horizontal direction.