Question

Find the average velocity of a projectile between the instants it crosses one third of the maximum height. It is projected with $u$ making an angle $\theta$ with the vertical.

• A. $u\cos \theta$
• B. $u$
• C. $u\sin \theta$
• D. $u\tan \theta$

Answer 1

The correct option is C $u\sin \theta$


The vertical velocities at the same height are in opposite directions and therefore their average sum $=0$.
​​​​​​​It is horizontal velocity which is uniform and hence $v_{avg}=u\sin \theta (=u_x)$.