Question

Find the base of a triangle, whose area is $90{\text{cm}}^2$ and height $12$ cm.

Answer 1

Area of Triangle =$\frac{1}{2}\times b\times h$

$GivenA=90c{m}^2$ and $h=12cm$

So $90=\frac{1}{2}\times b\times 12$

$b=15cm$