Question

Find the binding energy of an $\alpha$-particle from the following data:
Mass of helium nucleus$=4.001265$ a.m.u; mass of proton $=1.007277$ a.m.u. Mass of neutron $=1.00866$ a.m.u (take $1$ a.m.u$=931.5$ MeV)

Answer 1

$\alpha$ particle ${\to }_2^{4}He$

Given,

Mass of helium nucleus $=4.001265$ a.m.u

Mass of proton $=1.007277$ a.m.u

Mass of neutron $=1.00866$ a.m.u

We have Binding Energy, $E=△m{c}^2$

So, $△m=$ mass of Helium $-2$(mass of neutron + proton)

$=4.001265-2(1.007277+1.00866)=4.001265-4.031874=-0.030609u$

$E=△m{c}^2=0.030609\times 931.5MeV=28.5122835MeV$