Question

Find the breadth of a rectangle whose length is double of its breadth and perimeter is $720m$.

Answer 1

Calculate the Breadth of rectangle

Given,

Perimeter of rectangle $=720m$

Length of rectangle $=$double of its breadth

Let the breadth of rectangle is $b$$m$.

$\therefore$Length of rectangle $=$$2b$$m$

Perimeter of rectangle $=720m$

$\begin{array}{rcl}2(l+b)& =& 720m\\ 2(2b+b)& =& 720\\ 2\times 3b& =& 720\\ b& =& \frac{720}{6}\\ b& =& 120m\end{array}$

Hence, the breadth of rectangle is $120m$.