Find the center and radius of the circle.
${(x + 5)}^{2} + {(y - 3)}^{2} = 36$

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Solution

The general equation of circle is $(x - h)^{2} + (y - k)^{2} = r^{2}$ , where r is radius and (h,k)is centre of circle.
so acccording to given eqn ,
centre is (-5,3) as h=-5 ,k=3 here
and radius $, r^{2} = 36 \Rightarrow r = 6 u n i t s .$

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Find the centre and radius of the circles.
$(x + 5)^{2} + (y - 3)^{2} = 36$

{(x - 5)}^{2} + {(y - 3)}^{2} = 20

(x - \frac{1}{2})^{2} + (y + \frac{1}{3})^{2} = \frac{1}{36}

{(x - 2)}^{2} + {(y - 3)}^{2} = 36

{(x + 3)}^{2} + {(y + 2)}^{2} = 49

{(x - 4)}^{2} + {(y + 5)}^{2} = 64

{(x - 2)}^{2} + {(y + 5)}^{2} = 13

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