Find the centre and radius of each of the following circle.
${(x - 5)}^{2} + {(y - 3)}^{2} = 20$

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Solution

$(x - 5)^{2} + (y - 3)^{2} = 20$
$(x - 5)^{2} + (y - 3)^{2} = (20 \sqrt{5})^{2}$
Hence, $(5, 3)$ is the centre and $2 \sqrt{5}$ is the radius of the circle.

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Similar questions

Find the centre and radius of the circle (x + 5)² + (y – 3)² = 36

(x - \frac{1}{2})^{2} + (y + \frac{1}{3})^{2} = \frac{1}{36}

x^{2} + y^{2} = 25

(x - 5)^{2} + (y - 3)^{2} = 20

{(x - \frac{1}{2})}^{2} + {(y + \frac{1}{3})}^{2} = \frac{1}{36}

{(x - 2)}^{2} + {(y - 3)}^{2} = 36

{(x + 3)}^{2} + {(y + 2)}^{2} = 49

{(x - 4)}^{2} + {(y + 5)}^{2} = 64

x^{2} + y^{2} = 25

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