Find the centre and radius of the circle (x+5)2+(y−3)2=36
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Solution
The equation of the given circle is, (x+5)2+(y−3)2=36 ⇒{x−(−5)}2+(y−3)2=62 which is of the form (x−h)2+(y−k)2=r2 where h=−5,k=3 and r=6 Thus the centre of the given circle is (−5,3) while its radius is 6