Question

Find the centre and radius of the circles.
$2x^2+2y^2-x=0$

Answer 1

Given the equation of the circle is

$2x^2+2y^2-x=0$

or, $x^2+y^2-\frac{x}{2}=0$

or, $x^2-2.x.\frac{1}{4}+\frac{1}{4^2}+y^2=\frac{1}{4^2}$

or, ${(x-\frac{1}{4})}^2+y^2=\frac{1}{4^2}$.

From this equation we've the center is $(\frac{1}{4},0)$ and radius is $\frac{1}{4}$.