The centre and radius of the circle $2 x^{2} + 2 y^{2} - x = 0$ are

(\frac{1}{4}, 0) a n d \frac{1}{4}

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(- \frac{1}{2}, 0) a n d \frac{1}{2}

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(\frac{1}{2}, 0) a n d \frac{1}{2}

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(0, - \frac{1}{4}) a n d \frac{1}{4}

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Solution

The correct option is A $(\frac{1}{4}, 0) a n d \frac{1}{4}$
The circle is $x^{2} + y^{2} - \frac{1}{2} x = 0.$
Centre (-g, -f) = $(\frac{1}{4}, 0)$ and $R = \sqrt{\frac{1}{16} + 0 - 0} = \frac{1}{4} .$

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