The centroid G(x,y) of a triangle whose vertices are
(x1,y1)(x2,y2)(x3,y3) is given by
G(x,y)=G(x1+x2+x33,y1+y2+y33)
We have (x1,y1)=(4,−6),(x2,y2)=(3,−2),(x3,y3)=(5,2)
∴ The centroid of the triangle whose vertices are
(4,−6),(3,−2) and (5,2) is
G(x,y)=G(4+3+53,−6−2+23)
=G(4,−2)