find the change in momentum if the kinetic energy becomes 4 times the original value

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Solution

$K E_{i} = E K E_{f} = 4 K P = m o m e n t u m = \sqrt{2 m E} r e l a t i v e c h a n g e i n m o m e n t u m = \frac{f i n a l - i n i t i a l}{i n i t i l a} \frac{P_{f} - P_{i}}{P_{i}} = \frac{\sqrt{2 m \times 4 E} - \sqrt{2 m E}}{\sqrt{2 m E}} = 1 \times 100 = 100 %$

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A car is accelerated on a levelled road and attains a speed of 4 times its initial speed. In this process, the kinetic energy of the car :

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(d) becomes 16 times that of initial kinetic energy

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