Question

Find the circumference of a circle whose area is $301.84c{m}^2$.

Answer 1

Let radius of circle be 'r', then

Area of circle$=301.84c{m}^2$

$\Rightarrow \pi r^2=301.84c{m}^2\Rightarrow r^2=\frac{301.84\times 7}{22}=96.04\Rightarrow r=\sqrt{96.04}=9.8cm$

Therefore, circumference$=2\pi r=2\times \frac{22}{7}\times 9.8=61.6cm$