Question

Find the circumference of a semi-circle whose area is $436.59c{m}^2$

Answer 1

Let radius of circle be 'r', then $Areaofcircle=436.59c{m}^2$ $\pi r^2=436.59c{m}^2$ $r^2=\frac{436.59\times 7}{22}=138.92$ $r^2=138.92$ $r=11.8cm$ Therefore, circumference=$2\sqrt{\pi \times A}$ $=2\sqrt{\pi \times 436.59}$ $=74.069cm$