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Question

Find the coefficient of x5 in (1+2x)6+(1x)7 .

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Solution

General term is given by nCrxr
In First term the term containing x5 is given by
6C5(2x)56!5!(32)x56×32x5192x5(1)
In Second term the term containing x5 is given by
7C5(x)57!5!(x5)7×6×x542x5(2)
On adding both 19242=150
So the coefficient of x5 in given expression is 150

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