Find the complement of: $90^{o} - a$ .

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Solution

We know that, if two angles are complementary, then their sum is $90^{o}$ .
Then, the complement angle of $90^{o} - a$ is,
$= 90^{o} - (90^{o} - a)$
$= 90^{o} - 90^{o} + a$ $= a$ .

Therefore, the complement angle of $90^{o} - a$ is, $a$ .

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