Question

Find the complement of the angle $({90}^o-y)$.

Answer 1

We know that,

if two angles are complementary, then their sum is ${90}^o$.

Given, the angle is ${90}^o-y$.

Then, the complement of ${90}^0-y={90}^0-({90}^o-y)={90}^o-{90}^o+y=y^0$.