Question

Find the complementary of the angle ${30}^o$.

Answer 1

We know, two angles are said to be complementary, if the sum of their measures is ${90}^{\circ }.$

The given angle is ${30}^{\circ }$.

Let the measure of its complement be $x^{\circ }.$

Then,

$⟹$ $x+{30}^o={90}^o$

$⟹x={90}^o-{30}^o$

$⟹x={60}^{\circ }$

Hence, the complement of the given angle measures ${60}^{\circ }.$