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Question

Find the continued product:
(i) (x + 1)(x − 1)(x2 + 1)
(ii) (x − 3)(x + 3)(x2 + 9)
(iii) (3x − 2y)(3x + 2y)(9x2 + 4y2)
(iv) (2p + 3)(2p − 3)(4p2 + 9)

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Solution

i x+1x-1x2+1x2-x+x-1x2+1x2-1x2+1x22-122 according to the formula a2-b2 = a+ba-bx4-1.Therefore, the product of x+1x-1x2+1 is x4-1.

ii x-3x+3x2+9x2-32x2+9 according to the formula a2-b2 = a+ba-bx2-9x2+9x22-92 according to the formula a2-b2 = a+ba-bx4-81Therefore, the product of x-3x+3x2+9 is x4-81.

iii 3x-2y3x+2y9x2+4y23x2-2y29x2+4y2 according to the formula a2-b2 = a+ba-b9x2-4y29x2+4y29x22-4y22 according to the formula a2-b2 = a+ba-b81x4-16y4.Therefore, the product of 3x-2y3x+2y9x2+4y2 is 81x4-16y4.

iv 2p+32p-34p2+92p2-324p2+9 according to the formula a2-b2 = a+ba-b4p2-94p2+94p22-92 according to the formula a2-b2 = a+ba-b16p4-81.Therefore, the product of 2p+32p-34p2+9 is 16p4-81.

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