Question

Find the coordinates of vertex of the quadratic expression
$y=x^2-6x+12?$

• A. $(1,1)$
• B. $(3,3)$
• C. $(2,3)$
• D. $(2,2)$

Answer 1

The correct option is B

$(3,3)$

We saw that the vertex of the parabola or quadratic function $y-k=S(x-h{)}^2$ is $(h,k)$. So, we will try to express the given quadratic in this form. $y=x^2-6x+12$ can be expressed as
$y=(x-3{)}^2+3$
$\Rightarrow y-3=(x-3{)}^2$
Comparing it with $y-k=S(x-h{)}^2$, we get
$h=3$ and $y=3$
So, the vertex is $(3,3).$