Find the coordination number and oxidation number of X in the given compound.
[X(NH $_{3}$ ) $_{5}$ (SO $_{4}$ )]CI.

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Solution

The coordination number and oxidation number of X in the given compound [X(NH $_{3}$ ) $_{5}$ (SO $_{4}$ )]CI are 6 and 3 respectively. Five ammonia and one sulphate ligands are present. Hence, the coordination number is 6.Let the oxidation number of X be Y.
$Y + 5 (0) + (2 -) - 1 = 0$
$Y = 3$ .

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