Question

Find the cube root of $\frac{216}{343}$

• A. $\frac{7}{11}$
• B. $\frac{8}{9}$
• C. $\frac{6}{7}$
• D. $\frac{9}{11}$

Answer 1

The correct option is C $\frac{6}{7}$

We know $\frac{216}{343}=\frac{6^3}{7^3}$

Thus cube root of $\frac{216}{343}=\sqrt[3]{3\frac{6^3}{7^3}}=\frac{6}{7}$