Question

Find the current $I_2$.

• A. ${10}^{-4}A$
• B. $2\times {10}^{-4}A$
• C. $3\times {10}^{-4}A$
• D. $5\times {10}^{-4}A$

Answer 1

The correct option is A ${10}^{-4}A$

Let’s find the total current given by the battery first.
The resistors are in simple series-parallel combination where you can easily find out the equivalent resistance which comes out to be 12 Ohm.
I guess you would have figured that out already.
Applying the same old Ohm’s Law, V=IR
We get, I=0.001 Amperes.
This is the total current provided by the battery.

The other 5 resistors in the circuit have been replaced with their equivalent counterpart.
What we all need to find is I₁ as per question.
This is a trick question. As both resistors are of equal magnitude, total current gets equally distributed because as per Kirchhoff’s law no current can accumulate in between.
Thus, $I1=5\times {10}^{-4}$ A. Hence D.