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Question

Find the current through the battery in each of the circuits shown in figure (45-E5).


Solution

Both diodes are forward biased. Thus the net diode resistance is 0.

i=510×1010+10=55=1A

One diode is forward biased and other is reverse biased.

Current passes through the forward biased diode only.

i=VRnet=510+0=0.5A

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