Question

Find the currents through the resistances in the circuits shown in figure (45-E3).

Answer 1

(a) Since both the diodes are forward biased, net resistance = $2\Omega$

$i=\frac{2V}{2\Omega }=1A$

(b) One of the diodes is forward biased and other is reverse thus the resistance of one becomes $\infty$

$\therefore i=\frac{2}{2+\infty }=0A$

Both are forward biased. Thus the resistance is 0

$i=\frac{2}{2}=1A$

One is forward biased and other is reverse biased. Thus the current passes through the forward biased diode,

$\therefore i=\frac{2}{2}=1A$