Question

Find the day of the week on ${16}^{th}$ July, $1776$

• A. Tuesday
• B. Wednesday
• C. Monday
• D. Thursday

Answer 1

Answer: (A)

Tuesday

${16}^{th}$ July, $1776$ mean ($1775$ years $+$ $6$ months $+$ $16$ days)
Now, $1600$ years have $0$ odd days.
$100$ years have $5$ odd days.
$75$ years contain $18$ leap years and $57$ ordinary years and therefore $(36+57)$ or $93$ or $2$ odd days.
$\therefore$ $1775$ years given $0+5+2=7$ and so $0$ odd days,
Also number of days from $1^{st}$ Jan. $1776$ to ${16}^{th}$ July, $1776$
Jan. Feb. March April May June July
$31+29+31+30+31+30+16$
$=198$ days $=28$ weeks$+$ $2$ days $=2$ odd days
$\therefore$ Total number of odd days $=0+2=2$.
Hence the day on ${16}^{th}$ July, $1776$ was 'Tuesday'.