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Question

Find the de Broglie wavelength (in m) of an electron moving in the second Bohr orbit of hydrogen.

A
3.34×1010
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B
4.68×1010
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C
5.67×1010
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D
6.67×1010
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Solution

The correct option is D 6.67×1010
We know,
Velocity of an electron in Bohr's orbit is given by,
v=2.18×106×Zn m/sec

So, velocity of an electron in Bohr's second orbit of hydrogen is,
v=1.09×106 m/sec

Again,we know,
Mass of electron (me)=9.1×1031 kgPlanck's constant (h)=6.62×1034 Js
de Broglie wavelength (λ)=hmv=6.62×10349.1×1031×1.09×106 =6.67×1010 m

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