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Question

# Find the de Broglie wavelength (in m) of an electron moving in the second Bohr orbit of hydrogen.

A
3.34×1010
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B
4.68×1010
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C
5.67×1010
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D
6.67×1010
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Solution

## The correct option is D 6.67×10−10 We know, Velocity of an electron in Bohr's orbit is given by, v=2.18×106×Zn m/sec So, velocity of an electron in Bohr's second orbit of hydrogen is, v=1.09×106 m/sec Again,we know, Mass of electron (me)=9.1×10−31 kgPlanck's constant (h)=6.62×10−34 Js de Broglie wavelength (λ)=hmv=6.62×10−349.1×10−31×1.09×106 =6.67×10−10 m

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